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Posted 20 hours ago

ASHUTB – AB Shutter 3 Wireless Bluetooth Camera Shutter Remote Control Black

£9.9£99Clearance
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ZTS2023
Joined in 2023
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Fails to find previously paired devices, slow to find devices, and does not even bother to warn you if Bluetooth is not on at all. And to make it even better, it includes a mini stand for your phone or tablet to hold it steady while you take your picture. How does it connect according to hcitool con yet not be registered as an input device (and register any inputs)? If you can pair your accessory with some devices but not your iOS or iPadOS device, unpair the accessory from your other devices. It works perfectly on my iPad (as it used to do on my iPhone as well), but iPhone, though connecting via Bluetooth on my Mac Air, won't.

This is exactly what I needed - it makes sense because I am trying to actually connect to a device, not create a socket for exchange of data.

One interesting thing to note is that when I tried to connect to the device using the device address I had previously, it actually changed. Contents: The AB Shutter 3 remote control is black and comes with 1 CR2032 battery and 1 instruction manual [English language not guaranteed]. If you previously connected your Bluetooth accessory to your iOS or iPadOS device, unpair the accessory, put it back in discovery mode, then try to pair and connect it again. While I have come to the conclusion that there is no way to keep the device active that fits within our requirements, Mohamed's answer got me furthest down a path for an acceptable solution. I had my drummer control everything but I am a singer and I wanted to be able to move around the stage and use it in a solo setting.

Yes, it is possible to keep the other end of the connection awake as long as it accepts the input signals. Sounds like you're having issues trying to pair your third-party Bluetooth accessory with your iPhone 8. To find out whether your accessory is compatible with your iOS or iPad OS device, contact the manufacturer of the accessory.I have also used Python's native socket library (which have yielded me the same results): client_sock = socket.

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